Begin *

It looks like an open contest, and so it is indeed. The input to this puzzle consists of all English letters contained between two asterisks.
Please ignore all the spaces, punctuation marks, digits and special characters like #,&,@ etc and use the remaining letters to create valid English words of 3,4,5, or 6 letters without repeating any word twice or more.

Suppose you end up with A words of 6 letters, B of 5, C of 4 and D of 3. The leftover letters are of no value.
Consider your goal is to maximise the value of 7A+5B+4C+D.

What is your score?

*end

I understand why the program may not have found 69 words, yet one can assemble such a list. I did so using the SOWPODS word list.

ABWATT, ASSOTT, ATTACH, ATTAIN, ATWEEL,
ATWEEN, BASSLY, CENSES, CESSER, CESSES,
CHUFFY, CHURCH, DEGREE, DODDED, DOOCOT,
DOOWOP, EECHES, ELEVEN, ELPEES, EMCEED,
ESSIVE, FISHER, FESSES, FLYOFF, GAZOOS,
GUESTS, GUNNEN, HEEHAW, HERALD, HEROES,
HOLLOO, IMIDIC, INNING, IRITIC, KEWPIE,
LIMITS, MIRROR, MULLEY, NIGIRI, OOLONG,
OPERON, PANNED, PELLET, PENNON, POTATO,
POTOOS, PRAXIS, RORIER, ROTOLO, SCARPH,
STRAIT, SUNKEN, TAATAS, TACKET, TANTRA,
TURRET, TIRITI, TROLLS, TSKTSK, TUATUA,
TUNNED, TUNNEL, TWIBIL, TWILIT, ULITIS,
VOCALS, VOODOO, WEDDED, ZAFFAR

Extraneous letter: U

I do believe there are other combinations, and of those they may include more common words. Nonetheless, a score of 483 can be achieved.
7(69)+5(0)+4(0)+(0) = 483

Edited on March 31, 2021, 9:40 am

Posted by Dej Mar on 2021-03-31 09:24:53