All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Quadratic inequality leading to sum of roots (Posted on 2021-04-02) Difficulty: 2 of 5
Let P(x) be a real quadratic trinomial, so that for all x∈R the inequality P(x3+x)≥P(x2+1) holds. Find the sum of the roots of P(x).

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Solution - a question Comment 2 of 2 |
(In reply to Solution by Jer)

So I assume for your purposes p=x, and q= the 5th order polynomial you derived via expanding the inequality and collecting the terms on the LHS.<o:p></o:p>

However, I’m not sure your deductions that follow are correct?<o:p></o:p>

Doesn’t pq>=0 imply the following:<o:p></o:p>

If p>0, then q>=0, not q>0<o:p></o:p>

If p<0, then q<=0, not q<0<o:p></o:p>

If p=0, then q=b<o:p></o:p>

If q=0, p is limited to any root of the 5th order polynomial?<o:p></o:p>

or - my algebra is rusty - which could be true too!


  Posted by Kenny M on 2021-04-02 16:11:44
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information