Please find all real solutions to the following equation:
(x^2-11*x+29)^(x^2-17*x+72) = 1
Adapted from a problem by Presh Talwalkar.
Either
x^2-11*x+29 = 1
or
x^2-17*x+72 = 0
first case:
x^2 - 11x + 28 = 0
x = (11 +/- sqrt(121 - 112))/2 = (11 +/- 3) = 4 or 7
second case:
x = (17 +/- sqrt(289 - 288))/2 = 8 or 9
So the solution set is {4, 7, 8, 9}.
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Posted by Charlie
on 2021-04-06 10:59:00 |