A circle is contained in a quadrilateral with successive sides of lengths 3,6,5 and 8. Prove that the length of its radius is less than 3.
Not sure if it's this simple, but if I understand correctly the quadrilateral has opposite sides of lengths 3 and 5, so the width of the shape is <= 5 at any point. You obviously couldn't fit a circle with a diameter of 6 anywhere in there, right?
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Posted by tomarken
on 2021-04-09 13:35:35 |