(In reply to
re: Algebraic approach by Jer)
This was a lot of work, but I think I kept track of everything.
As I pointed out in the previous:
[1]=0
[2]=0
[3]=1
[4]=0
[5]=-1
and we seek
{5}+{4}+{3}+{2}+{1}+{0}
See the other posts for the definitions of [n] and {n}
{0}=1
I have to omit the work. It's really complicated. But if you square each of [n] you get {n} + possibly other products.
[5]^2={5}
(-1)^2={5}
1={5}
[4]^2={4}+2*[3][5]
0={4}+2*1*-1
2={4}
[3]^2={3}+2*[2][4]+4*[1][5]
1^2={3}+2*0*0+4*0*-1
1={3}
[2]^2={2}+2*[1][3]+4*[4]
0^2={2}+2*0*1+4*0
0={2}
[1]^2={1}+2*[2]
0^2={1}+2*0
0={1}
So the final sum is
{5}+{4}+{3}+{2}+{1}+{0}
1+2+1+0+0+1 = 5
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Posted by Jer
on 2021-05-11 08:30:55 |
re(2): Algebraic approach
