Find all functions f:R->R such that for all x,y∈R
f(xy + 1) = f(x+y) + f(x)f(y)
This turns out to be pretty straightforward,
With x = y = 1 we get
f(2) = f(2) + f(1)^2, so f(1) = 0
with x = y = 0 we get
f(1) = f(0) + f(0)^2 = 0 so f(0) = 0
with y = 0 (and x variable), we get
f(1) = 0 = f(x) + f(x)f(0) = f(x)
|
Posted by FrankM
on 2021-08-12 23:03:58 |