(In reply to
re: Poor attempt at an explanation by broll)
No, see my example again. You aren't considering k and n can be different numbers. For other pairs (k,n) each side can have the same number of factor of two.
The next example is (68,11) both have 66 factors of 2.
By this time the factors of 3 have widely diverged at 31 and 6 respectively.
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Posted by Jer
on 2021-08-15 13:25:09 |