Let a,b be reals and f(x)=ax+b+9/x. Prove that there exists x0∈[1,9], such that |f(x0)|≥2.
The problem seems so completely trivial that I must be misinterpreting it greatly.
When I say a=1, b=1, x0=3, f(x0) = |f(x0)| =7
|f(x0)|≥2, x0∈[1,9]
where have I gone wrong?
Thanks