Determine the present ages of each of the three siblings Toby, Julie and Melanie from the following clues:
- 10 years from now Toby will be twice as old as Julie was when Melanie was 9 times as old as Toby.
- 8 years ago, Melanie was half as old as Julie will be when Julie is 1 year older than Toby will be at the time when Melanie will be 5 times as old as Toby will be 2 years from now.
- When Toby was 1 year old, Melanie was 3 years older than Toby will be when Julie is 3 times as old as Melanie was 6 years before the time when Julie was half as old as Toby will be when Melanie will be 10 years older than Melanie was when Julie was one-third as old as Toby will be when Melanie will be 3 times as old as she was when Julie was born.
Time now is t = 0
Julie is age J
Toby is age T
Melanie is age M
To get to a date when X (at age X now) reaches age Ad (destination age), take Ad - X.
To get to the age of X at time Td (destination time), take X + Td.
1.
Nine times Toby's age 9T
When was Melany that age 9T - M
How old was Julie then 9T - M + J
Twice that 18T - 2M + 2J
When will Toby be that age 17T - 2M + 2J
This is said to be at t=10
10 = 17T - 2M + 2J
2.
Toby's age 2 years from now T+2
Five times that 5T + 10
When will Melanie be that age 5T + 10 - M
Toby's age at that time 6T + 10 - M
One year older than that 6T + 11 - M
When will Julie be that age 6T + 11 - M - J
What's half that 3T + 11/2 - M/2 - J/2
When is Melanie that 3T + 11/2 - 3M/2 - J/2
That's said to be at t = - 8
-8 = 3T + 11/2 - 3M/2 - J/2
3.
Julie's age now (t=0) J
Melanies age at Julie's birth M-J
Three times that 3M-3J
When will she be 3 times that 3M-3J-M = 2M-3J
(since now is t=0)
How old will Toby be then T+2M-3J
One third of that (T+2M)/3 - J
When was Julie that age (T+2M)/3 - 2J
(should be a negative
value relative to t=0)
How old was Melanie then M+(T+2M)/3 - 2J
(adding a negative value)
= T/3 + 5M/3 - 2J
Ten years older than that T/3 + 5M/3 - 2J + 10
When will Melanie be that T/3 + 2M/3 - 2J + 10
How old will Toby be then 4T/3 + 2M/3 - 2J + 10
What's half that 2T/3 + M/3 - J + 5
When was Julie that age 2T/3 + M/3 - 2J + 5
Six years before that was t= 2T/3 + M/3 - 2J - 1
How old was Melanie then 2T/3 + 4M/3 - 2J - 1
What's 3 times that 2T + 4M - 6J - 3
When will Julie be that age 2T + 4M - 7J - 3
How old will Toby be then 3T + 4M - 7J - 3
Three years older than that 3T + 4M - 7J
When was Melanie that age 3T + 3M - 7J (this is negative,
i.e. the past)
Toby was 1 then so now he's 1 - 3T - 3M + 7J
T = 1 - 3T - 3M + 7J
or
4T = 1 - 3M + 7J
eqns =
[10 == 2*J - 2*M + 17*T, -8 == 3*T - (3*M)/2 - J/2 + 11/2, 4*T == 7*J - 3*M + 1]
soln=solve(eqns,[T,M,J])
soln.T
ans =
58/49
>> soln.M
ans =
1919/196
>> soln.J
ans =
927/196
Wolfram Alpha agrees, as
solve 10 = 17T - 2M + 2J, -8 = 3T + 11/2 - 3M/2 - J/2, 4T = 1 - 3M + 7J for T,M,J
yields the same answers: 58/49 for T, 1919/196 for M and 927/196 for J.
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Posted by Charlie
on 2022-01-08 18:11:58 |