perplexus.info :: Numbers : Inconsiderable Five-Prime Ratio Illation

Inconsiderable Five-Prime Ratio Illation (Posted on 2022-01-12)

p₁, p₂, p₃, p₄ and p₅ are 5 distinct prime numbers, with p₁< p₂<p₃<p₄<p₅, that satisfy this relationship:

 
 p₁*p₂*p₃*p₄*p₅
------------------- = p_x* p_y 
p₁²+p₂²+p₃²+p₄²+p₅²

where p_x and p_y are distinct prime numberε(p₁,p₂,p₃,p₄,p₅).

Determine the minimum value of p_x* p_y.
What is the next smallest value of p_x* p_y?

See The Solution Submitted by K Sengupta

Rating: 4.0000 (2 votes)

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Comment 4 of 4 |

Posted by K Sengupta on 2022-02-18 20:48:05

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