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Inconsiderable Five-Prime Ratio Illation (Posted on 2022-01-12) Difficulty: 3 of 5
p1, p2, p3, p4 and p5 are 5 distinct prime numbers, with p1< p2<p3<p4<p5, that satisfy this relationship:
 
 p1*p2*p3*p4*p5
------------------- = px* py 
p12+p22+p32+p42+p52

where px and py are distinct prime numberĪµ(p1,p2,p3,p4,p5).
Determine the minimum value of px* py.
What is the next smallest value of px* py?

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (2 votes)

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No Subject | Comment 3 of 4 |
Your article is very good and useful, thank you for sharing, bk8 hopes that next time you will have more good articles to send to all readers.
  Posted by hoadao3493 on 2022-02-18 09:01:25
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