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Inconsiderable Five-Prime Ratio Illation (Posted on 2022-01-12) Difficulty: 3 of 5
p1, p2, p3, p4 and p5 are 5 distinct prime numbers, with p1< p2<p3<p4<p5, that satisfy this relationship:
 
 p1*p2*p3*p4*p5
------------------- = px* py 
p12+p22+p32+p42+p52

where px and py are distinct prime numberĪµ(p1,p2,p3,p4,p5).
Determine the minimum value of px* py.
What is the next smallest value of px* py?

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (2 votes)

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No Subject Comment 4 of 4 |

  Posted by K Sengupta on 2022-02-18 20:48:05
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