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Arithmetic inverse trigonometry (Posted on 2021-07-07) Difficulty: 3 of 5
Find arctan(tan 15° * tan 21° * tan 27°).

No Solution Yet Submitted by Danish Ahmed Khan    
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Some Thoughts By Scientific Hand Calculator Comment 1 of 1
The product: (tan 15*tan21*tan27) is approximately:
-4.28046154195 (correct to 11 places) and:
arctan(-4.28046154195) is:
approximately- equal to -1.34129286142 (correct to 11 places) degrees , which seems to be the desired end result.

I have neither been able to derive the end result analytically nor have I been able to fathom its significance.

Edited on May 14, 2022, 11:25 pm
  Posted by K Sengupta on 2022-05-14 22:46:05

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