For every positive integer
n:
10n+18*n-1
is divisible by
27.
The above statement can be proven by more than one way.
Find at least 2 distinct methods.
10^n + 18*n -1 10^n - 1 18*n
------------------------ = -------------- + ---------
9 9 9
= 11.....11 (n 1s) + 2*n
Now, {11....11(n 1s) +2*n} (mod 3)
= n (mod 3) + 2*n (mod 3)
= 3*n (mod 3)
= 0 (mod 3)
Consequently, 10^n+18*n-1 is divisible by 9*3 = 27