The least common multiple (LCM) of 2 numbers is the smallest number that they both divide evenly into.
e.g.:
LCM(8,10)=40
LCM(17,11)=187
For any integer n, show that LCM(9n + 8, 6n + 5) = 54n^2 + 93n + 40.
We observe that for integers 2 and -3,
2(9n+8)+(-3)(6n+5)=1
Therefore, in terms of Bezout's Lemma, we must have:
gcd(9n+8, 6n+5) = 1
We know that:
a*b
lcm(a,b) = ---------------
gcd(a,b)
Then, lcm(9n+8, 6n+5)
= (9n+8)(6n+5), since gcd(9n+8,6n+5) = 1
= 54n^2 + 45n+48n+40
= 54n^2 +93n+40
Edited on May 21, 2022, 10:18 am