perplexus.info :: Geometry : Closest approaches

Closest approaches (Posted on 2022-01-14)

ABCD is a unit square with movable point E on side CD.
P₁ is on the same side of Line AE as D and P₂ is on the other side such that AEP₁ and AEP₂ are equilateral triangles.

(A) Find the smallest possible distance P₁D.

(B) Find the distance CE that minimizes P₂B.

No Solution Yet Submitted by Jer

Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

Puzzle Answer

Comment 3 of 3 |

(A) The required smallest distance P_1D is 0.5

(B) The required distance CE that minimizes P_2B is 0.5

Posted by K Sengupta on 2022-07-07 00:42:37

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info