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Closest approaches (Posted on 2022-01-14) Difficulty: 3 of 5
ABCD is a unit square with movable point E on side CD.
P1 is on the same side of Line AE as D and P2 is on the other side such that AEP1 and AEP2 are equilateral triangles.

(A) Find the smallest possible distance P1D.

(B) Find the distance CE that minimizes P2B.

No Solution Yet Submitted by Jer    
Rating: 3.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle AnswerK Sengupta2022-07-07 00:42:37
New postLacy Adams2022-03-27 05:03:29
SolutionsolutionCharlie2022-01-14 11:07:23
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