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Numbers À Propos (Posted on 2005-09-20) Difficulty: 3 of 5
If letters are assigned the values A=1, B=2, ..., Z=26, then any word will have a total value equal to the total of the values of its letters.

Doing this will give square a value of 81, which is a perfect square. The word prime will have a value of 61, which is prime. Also, odd will evaluate as 23, which is odd, and even as 46, which is even.

If we were to change the values of three of the letters of the alphabet, so that the other 23 letters had the same values as above, but the chosen three had their values scrambled, words would have different values. An example of scrambling the values of three letters would be if I chose B, E and H, to give B=8 (ordinarily the value for H), E=2 (ordinarily the value for B) and H=5 (ordinarily the value for E).

With a particular scrambling of the values of some three letters, square has a different value, but is still a perfect square; prime has a lower value but is still a prime; and odd is still odd and even still even, though at least one of odd or even has a different value from before.

What are the three letters that had their values changed, and what are those values?

See The Solution Submitted by Charlie    
Rating: 4.2000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Puzzle Solution Comment 3 of 3 |

Original assignment is:
ODD         EVEN         PRIME        SQUARE
23              46               61                 81

Changing the assignment of (U, R, D) --> (21, 18, 4) to (U, R, D) --> (18, 4, 21), we have:
ODD         EVEN          PRIME         SQUARE
57               46               47                64


  Posted by K Sengupta on 2022-07-08 22:56:35
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