perplexus.info :: Just Math : A special equation

A special equation (Posted on 2020-02-19)

Nonzero real numbers a, b, and c are such that

a²+b+c=1/a
b²+c+a=1/b
c²+a+b=1/c

Find (a-b)(b-c)(c-a)

No Solution Yet Submitted by Danish Ahmed Khan

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Puzzle Answer

Comment 4 of 4 |

The required value of (a-b)(b-c)(c-a) is 0.

*** Looks difficult! Will try my best to posit an analytic solution if I can.

Posted by K Sengupta on 2022-07-25 22:07:15

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