perplexus.info :: Just Math : Digits 251 in sequence

Digits 251 in sequence (Posted on 2009-01-05)

When written as a decimal, the fraction m/n (with m < n, both positive integers) contains the consecutive digits 2, 5, 1 (in this order). Find the smallest possible n.

See The Solution Submitted by pcbouhid

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Puzzle Answer

Comment 6 of 6 |

The required smallest possible value of n is 127, and 32/127= ~0.251

Edited on January 31, 2024, 7:23 am

Posted by K Sengupta on 2022-07-28 04:26:54

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