perplexus.info :: Calculus : Minimum Value

Minimum Value (Posted on 2002-06-19)

Given:

    x,y,z > 0
    xy+yz+zx <= 3/4

and

    P=x+y+z+(1/x)+(1/y)+(1/z)

Find the Minimum Value of P. Find x, y, and z when P = Minimum Value.

See The Solution Submitted by vohonam

Rating: 3.2500 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

Puzzle Answer

Comment 18 of 18 |

The required minimum value is given by:

P(x, y, z) =7 -----, when (x, y, z) = (1/2, 1/2, 1/2)

*** Interesting !! Must strive to derive an independent analytic explanation of my own!!

Posted by K Sengupta on 2022-08-15 07:16:52

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