Begin with an N-digit positive integer (no leading zero) and from it create N more integers (each N-1 digits long) by sequentially removing the units digit, or the tens digit, etc from the original number.
The sum of these N+1 integers is the final result.

For example, 1234 + 123 + 124 + 134 + 234 = 1849

1) What original number yields 2022 as the result?
2) How about 487929?
3) If the original number is represented by the concatenation of digits "d_N-1 d_N-2 ... d₂ d₁ d₀", provide an algebraic formula for the final result.

The formula in 3) should be a function of N, i, and the d_i:
where the d_i are the individual digits, and i is the position of the digit.
Note that I am representing the ones digit as i=0.

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Posted by nguyentra3493 on 2022-08-19 14:18:20