All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Nonn, easy, nice. (Posted on 2022-11-23) Difficulty: 3 of 5

To prove:

The sum of the first n even squares, less the sum of the first n squares, is equal to the nth square, plus the nth cube, plus the nth triangular number.

The sum of the first n odd squares, less the sum of the first n squares, is equal to the nth cube, less the nth triangular number.

No Solution Yet Submitted by broll    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Just the first one | Comment 2 of 5 |
(In reply to Just the first one by Larry)

first n odd squares sum to:

(4 n^2 - n) / 3

Edited on November 23, 2022, 11:15 am
  Posted by Steven Lord on 2022-11-23 11:14:40

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information