perplexus.info :: Calculus : Minimum Value

Minimum Value (Posted on 2002-06-19)

Given:

    x,y,z > 0
    xy+yz+zx <= 3/4

and

    P=x+y+z+(1/x)+(1/y)+(1/z)

Find the Minimum Value of P. Find x, y, and z when P = Minimum Value.

See The Solution Submitted by vohonam

Rating: 3.2500 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

oops

| Comment 14 of 18 |

somehow i missed the nifty xy+yz+zx <= 3/4

Posted by lyeshea on 2002-07-02 12:46:36

Please log in:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info