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Simultaneous Settlement VII (Posted on 2023-01-08) Difficulty: 3 of 5
Each of m and n is a complex number that satisfies this set of simultaneous equations:
  • mn - n2 = 3
  • mn + 2m2 = 1
Without solving for m and n, determine the value of mn

Note: mn is the product of m and n, rather than their concatenations.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Solution computer solution | Comment 1 of 6
Refer to mn as y:

y-n^2=3
y+2*(y/n)^2=1

Program:

syms y n
eq1=y-n^2==3;
eq2=y+2*(y/n)^2==1;
s=solve([eq1 eq2],y,n);
s.y

finds

2/3 - (5^(1/2)*1i)/3
(5^(1/2)*1i)/3 + 2/3
2/3 - (5^(1/2)*1i)/3
(5^(1/2)*1i)/3 + 2/3

In easier-to-read form:

y = mn = 2/3 +/- sqrt(5)/3 i

repeated twice for some reason, probably paired with different values of n.

Approximately

          0.666666666666667 -      0.74535599249993i
          0.666666666666667 +      0.74535599249993i

  Posted by Charlie on 2023-01-08 08:56:36
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