perplexus.info :: Just Math : Log Value Extrication

Log Value Extrication (Posted on 2023-01-22)

Each of M and N is a positive real number that satisfies the following simultaneous equations:

Determine the value of log₃₅(28) in terms of M and N.

See The Solution Submitted by K Sengupta

Rating: 4.0000 (1 votes)

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solution

Comment 2 of 2 |

14^M = 7

14^N = 5

35 = 14^(M+N)

log14(35) = M+N

log28(35) = (M+N)/log14(28)

log35(28) = log14(28)/(M+N)

= (M + log14(4))/(M+N)

Posted by Charlie on 2023-01-22 11:02:41

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