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Arithmetic Sequence Crossed Integer Determination Puzzle (Posted on 2023-02-12) Difficulty: 3 of 5
+----+----+----+----+
| 23 |    |    |    | 
+----+----+----+----+
|    |    | 64 |    |
+----+----+----+----+
|    |  N |    |    | 
+----+----+----+----+
|    |    |    |101 |  
+----+----+----+----+
In the 4x4 grid provided above:
  • Each the 16 values appearing in the 16 cells is a positive integer.
  • The 4 values corresponding to each of the 4 rows are in arithmetic sequence.
  • The 4 values corresponding to each of the 4 columns are in arithmetic sequence.
Determine the total number of distinct positive integer values that N can assume.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Solution with correction | Comment 4 of 6 |
(In reply to Solution by Larry)

With the additional constraint, which I missed, that all integers in the grid must be positive, the number of possible values for N is finite.
N is still given by the equation: 
N = 135 - 5a, but with -7 <= a <= 19.

So that is 27 values for N in {40, 45, ..., 165, 170}

  Posted by Larry on 2023-02-12 15:56:05
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