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10 Ultimate cribbage hands (Posted on 2006-07-18) Difficulty: 4 of 5
Consider laying out 10 sets of 4 cards plus a turn-up, from a single deck of cards, forming what might appear to be 10 cribbage hands including a different turn-up for each. (Two cards will be left over.)

How could these sets be arranged to maximize the sum of the scores of these hands?

http://en.wikipedia.org/wiki/Cribbage may provide you with some guidance.
Note: Each hand has its own turn-card so a single jack in each hand could be the right jack.

See The Solution Submitted by Jer    
Rating: 3.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Puzzle Thoughts Comment 6 of 6 |
A A, 2, 2, 3 = 16
A, A, 2, 2, 3 = 16
4, 4, 4, 4, 3 = 20
6, 6, 6, 6, 3 = 24
7, 7, 8, 8, 9 = 24
7, 7, 8, 8, 9 = 24
10,10,10,10, 5 = 20
J, J, J, J, 5 = 21
Q, Q, Q, Q, 5 = 20
K, K, K, K, 5 = 20
===================
Total 205

The two cards left over are two 9s.

Edited on May 8, 2023, 11:05 pm
  Posted by K Sengupta on 2023-05-08 23:03:47

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