Let start with the second equation and complete the squares in the radicands. Then we have
sqrt[(x-2)^2 + (y+1)^2] + sqrt[(x-10)^2 + (y-5)^2] = 10
Now the two radicands describe the distance from (2,-1) to (x,y) and (10,5) to (x,y). So what we actually have is an ellipse with foci of (2,-1) and (10,5) and the sum of distances equals 10.
But the distance from (2,-1) to (10,5) is also 10. This means our ellipse is a degenerate ellipse consisting solely of the line segment from (2,-1) to (10,5).
The equation of the line passing through (2,-1) and (10,5) is 3x-4y=10. Then the intersection of this line with 3x+4y=26 is (6,2). This does lay on the segment spanning (2,-1) to (10,5), so it is a valid solution.