Two concentric circles are drawn with chord AB drawn on the larger circle.
AB cuts through the smaller circle at points C and D.
It is known that AC=7, CD=6, and DB=7.
What is the area between the two circles?
For comparison, the classic problem
What's the area? is a version where the chord tangent to the inner circle.
Let O be the common center. Call the point where the perpendicular radius meets the chord X, and XO=x. The distance AO=R and CO=r so that we seek (R^2-r^2)pi.
The order of the points C and D is not specified.
Case 1: Order is A-C-D-B.
CX=6/3=3, AX=7+3=10
x^2+3^2 =r^2
x^2+10^2=R^2
R^2-r^2=100-9=91
Area= 91pi
Case 2: Order is A-D-C-B
CX=6/3=3, AX=7-3=4
x^2+3^2=r^2
x^2+4^2=R^2
R^2-r^2=16-9=7
Area= 7pi
|
Posted by Jer
on 2023-07-19 08:57:10 |