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Derive a formula (
Posted on 2023-07-27
)
Given
a+b+c=0 and abc=4
Evaluate S=a^3+b^3+c^3
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Submitted by
Ady TZIDON
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Puzzle Solution
| Comment 1 of 3
a+b+c=0
Or, a+b=-c
Or, a^3+b^3+3ab(a+b)= -c^3
Or, a^3+b^3+c^3+3ab*(-c)=0
Or, a^3+b^3+c^3=3abc
Or, a^3+b^3+c^3=3*4
Or, a^3+b^3+c^3=12
QED
Posted by
K Sengupta
on 2023-07-27 09:12:29
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