Using only p&p and a hand-calculator, determine the value of this expression:
1 1 1
1 + - + --- + ----- + ...
3 3x6 3x6x9
Rewrite each term as a quotient of power of 1/3 and a factorial:
(1/3)^0/0! + (1/3)^1/1! + (1/3)^2/2! + (1/3)^3/3! + ...
Then this is simply the series expansion of e^x evaluated at 1/3.
Then the infinite sum evaluates to e^(1/3), and any scientific calculator can easily compute the numeric value as 1.395612425...