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A cubic equation (Posted on 2023-09-14) Difficulty: 3 of 5
Solve in positive integers:

x^3=y^3+2y^2+1

Source: Bulgarian Math. Competition

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Puzzle Answer Comment 2 of 2 |
Only three integer solutions exist for the given equation.
They are: (x,y) = (1,0), (1,-2), and (-2,-3).
No positive integer pair corresponds to the given equation. 

  Posted by K Sengupta on 2023-09-15 01:36:41
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