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Additively Quadratic 2 (Posted on 2023-11-11) Difficulty: 3 of 5
Determine all possible positive integer triplet(s) (F, G, H) such that each of F and G is a prime with F ≤ G, and:

F(F+2) + G(G+2) = H(H+5)

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Some Thoughts A set of solutions Comment 4 of 4 |
Looking at the lists that Charlie and Larry generated, some solutions popped out at me:

      3      19      18 
      7      67      66 
     13     199     198 
     37    1447    1446 
     61    3847    3846 
     73    5479    5478 
    139   19603   19602 
    157   24967   24966

I noticed all these have H=G-1, then a little poking I made a generator: {F,G,H} = {F, (F+1)^2+3, (F+1)^2+2}  This satisfies the problem for any F (ignoring primality requirements)

The OEIS has Sequence A350676: Primes p such that p^2 + 2*p + 4 is prime.  Any member of A350676 can be substituted for F to create an entire class of solutions to the problem.

  Posted by Brian Smith on 2023-11-11 14:20:03
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