A quartic polynomial is given to have two distinct inflection points, call those points I1 and I2. A line is drawn through these inflection points and intersects the quartic at two other points, call those points P1 and P2.
The four points will lay along the line in the order P1, I1, I2, P2.
Show that segments P1I1 and P2I2 are congruent.
Find the ratio of segment P1I1 to I1I2.
Letting b=C=D=0
(I didn't prove the solution is independent of C.)
P(x)=x^4/12-ax^3/6
P(a)=-a^4/12
So the line passes through (0,0) and (a,P(a)) and has eq. y=-a^3x/12
Find the intertsection of this line with y=P(x). This involves solving a degree 4 equation but since we know it has roots at 0 and a so it can be factored as
x(x-a)(x^2-ax-a^2)
The final factor will give P1 and P2
Solving this quadratic gives
x=a(1+/-sqrt5)/2
The positive root is the golden ratio = phi
P1I1=P2I2=a/phi
P1I2/I1I2=phi
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Posted by Jer
on 2023-11-24 19:16:15 |