All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Inflection Point Line (Posted on 2023-11-24) Difficulty: 3 of 5
A quartic polynomial is given to have two distinct inflection points, call those points I1 and I2. A line is drawn through these inflection points and intersects the quartic at two other points, call those points P1 and P2.

The four points will lay along the line in the order P1, I1, I2, P2.
Show that segments P1I1 and P2I2 are congruent.
Find the ratio of segment P1I1 to I1I2.

No Solution Yet Submitted by Brian Smith    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution The finish Comment 2 of 2 |
Letting b=C=D=0
(I didn't prove the solution is independent of C.)

P(x)=x^4/12-ax^3/6

P(a)=-a^4/12

So the line passes through (0,0) and (a,P(a)) and has eq. y=-a^3x/12

Find the intertsection of this line with y=P(x).  This involves solving a degree 4 equation but since we know it has roots at 0 and a so it can be factored as
x(x-a)(x^2-ax-a^2)
The final factor will give P1 and P2
Solving this quadratic gives
x=a(1+/-sqrt5)/2 
The positive root is the golden ratio = phi

P1I1=P2I2=a/phi

P1I2/I1I2=phi

  Posted by Jer on 2023-11-24 19:16:15
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information