Decode this message.
EE73251
4924A8A
4E24304
4A24A84
4973244
(The layout of the code, the types of characters used, and the title of the puzzle are all clues to breaking the code.)
(In reply to
re: Tricky indeed by gregada)
Continuing with the logic of the previous post:
Now adding rows, you get:
28
29
30 (count 0 as 10)
24
33
which transfers into
c
d
e
x
g
once again you have 3 out of 4 letters needed for 'code' and have two remaining. now let's see what's left to do:
we need to combine q and n to get k to complete tricky and we need to combine x and g to get o to complete code.
q=17, n=14 q-n=3 n-3=11 11=k so we got k
g=33, x=24 g-x=9 x-9=15 15=o so we got o
so column sums contain word tricky and row sums contain word code.
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Posted by gregada
on 2003-08-11 11:44:34 |
Got it!!
