To go along with Factorial Sequence, I present Factorial Sequence II. You can approximate the length of x! by multiplying x*log(x/e).
Now, using this knowledge, find the value at which the length of x! is equal to 1,000,000,000?
There does not exist any value of x, so that x! rounds to 1,000,000,000.
The nearest value is x= 130202808 for which x! rounds to 999,999,999 and x = 130202809 for which x! rounds to 1000,000,008.
Edited on December 18, 2023, 11:22 am