There is a country with exactly 1,000,000,000 residents. You are given the following information about the residents:

1. If a pie chart was drawn comparing smokers and non smokers, the area of non smokers would be 3.8 times bigger than the area of smokers.

2. Approximately 23 out of 37 of the residents drive

3. A ratio of appoximately 26:7 people drink alcohol and do not drink alcohol respectively

4.If a bar graph was drawn showing percentages of people who own a computer and who don't own a computer with a scale of 2.5 cm : 1%, the bar showing people who do own a computer would be 165 cm longer than the bar showing people who do not own a computer.

Approximately how many people in this country smoke AND drink alcohol AND drive AND own a computer? (Assume that people who do any of the things have an equal chance of doing any other things as anybody else, eg somebody who smokes and drinks alcohol as an equal chance of owning a computer as somebody who drives).

* By "Approximately" I mean "To the nearest person".

not sure if i'm doing this right, but wouldn't the probability of a person doing all of the activities listed be the probabilities of the person doing each individual event multiplied together? If so, I obtain the probability for a person to be a smoker, drinker, driver, and computer owner to be:

(1/4.8)*(23/37)*(26/33)*(83/100) = .084688

which means that approximately 84688097 (.084688*1,000,000,000) people in the country would smoke, drink, drive and own a computer.

Posted by DuCk on 2003-08-12 07:48:43