A string of
2001 digits begins with a "
6". Any number formed by two consecutive digits is divisible by either
17 or
23.
What is the last digit in this sequence?
What if the sequence had 2002 digits?
2001 = 6
2002 = 9
the only possible sequence is 69234 repeating
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Posted by FatBoy
on 2003-08-12 09:40:50 |