Let x, y, z be real numbers that satisfy this system of equations:
• xy+4z=60
• yz+4x=60
• zx+4y=60
Let S be the set of possible values of x.
Determine the sum of the squares of the elements of S.
Wolfram Alpha lists these possibilities:
x = -10 and y = -10 and z = -10
x = 4 and y = 4 and z = 11
x = 4 and y = 11 and z = 4
x = 6 and y = 6 and z = 6
x = 11 and y = 4 and z = 4
The possible values of x are
(-10, 4, 6, 11)
The sum of their squares is 273.
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Posted by Charlie
on 2023-12-25 13:12:27 |