Define:
d/dx(f(x)) = f'(x)
where f'(x) = gradient (or slope) of f(x) at x = x.
Prove that:
d/dx(x^2) = 2x
without using calculus.
Let y= Cx+D be a tangent to y= x^2.
Then, there is precisely one solution to the quadratic equation:
x^2-Cx-D =0
Then, C^2=4CD
=> C= 4D
Therefore:
x=-(-D)/2C = D/2*1 = D/2
=> D= 2x
Now, in y= Cx+D, C is the gradient.
Therefore, d/dx(x^2)= 2x
Edited on January 29, 2024, 7:25 am