perplexus.info :: Just Math : Powers of x and y

Powers of x and y (Posted on 2017-01-21)

Find all possible couples of distinct integers (x,y) satisfying the equation: x^4 + y = x^3 + y^2

No Solution Yet Submitted by Ady TZIDON

Rating: 4.0000 (1 votes)

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Puzzle Answer

Comment 4 of 4 |

(0, 0), (0, 1), (1, 0), (1, 1), (-1, -1) and (-1, 2) represents all possible integer solutions to the given equation.

Edited on February 5, 2024, 7:38 am

Posted by K Sengupta on 2024-02-04 08:51:37

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