To find solutions consider this as a quadratic in x: (2)x^2+(2y)x+(5y^2-20)=0. The discriminant of this is 160-36y^2 which is only a perfect square for y= +/- 2.
This leads to the four points (0,2), (-2,2), (0,-2), (2,-2) which is a parallelogram with base 2 and height 4 which has area 8.
Edit: Silly me. It clearly states area. The side lengths are simply 2 and 2sqrt(5) for a total perimeter 4+4sqrt(5)
Edited on February 19, 2024, 1:58 pm
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Posted by Jer
on 2024-02-19 07:59:22 |