The number 24 is a multiple of 6, and its reversal, 42, is also a multiple of 6.
What is the probability that the reversal of any randomly-chosen multiple of 6 is also a multiple of 6?
I am feeling a bit contrary today, so I will give a different answer.
I agree that the reverse of an integer divisible by 6 is also divisible by 6 if the initial digit was 2 or 4 or 6 or 8.
And I agree that the initial digit is even approximately 4 times out of 9 (44.4%) if you are considering all 3 digit or 4 digit or 5
digit numbers.
But what if you consider all integers less than 200,000? Then only 22.2% start with an even digit.
And what if you consider all numbers between a random x and y, or all numbers without an upper bound? Benford's law arguably says that 17.6% of numbers start with a 2, 9.7% with a 4, 6.7% with a 6 and 5.1% with an 8. so, adding them up, my answer is 39.1%.
Benford's Law
