A room has a 20-foot ceiling. From the ceiling hang two electrical cords 16 feet and 18 feet long.
At the end of one is a plug, and at the end of the other is a receptacle. The electrician is tall, and can reach up to 8 feet from the floor.
How far apart can the two cords be, yet still be possible for the electrician to connect them?
If the electrician can attach a rope to the shorter one so that while moving the end of the longer one to where the connection is to be made, he can retrieve the shorter one to that location (or vice versa), then the connection can be made 12 feet below the ceiling, with the two cords pulled taut to form the hypotenuses of two right triangles with a common 12-foot leg.
Then the arithmetic is
>> sqrt(16^2-12^2)+sqrt(18^2-12^2)
ans =
23.9994131092571
so that the separation of the two cords can be almost 24 feet.
If the electrician has no rope he must bring the longer cord to where the shorter one is, and the hypotenuse of the single right triangle formed is the 18-foot length of the longer cord and the vertical leg is 16 feet, and the arithmetic is
>> sqrt(18^2-16^2)
ans =
8.24621125123532
or almost 8 1/4 feet.
Of course the electrician also has a span between his left and right hands, so he could expand a little on this, maybe something like 5 more feet.
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Posted by Charlie
on 2024-03-19 13:18:17 |