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Odd divisor summation (Posted on 2024-03-21)

For each positive integer n, let D_n be the greatest odd divisor of n. (For example, D₁₆₈ = 21.) Find D₁ + D₂ + D₃ + ⋅ ⋅ ⋅ + D₂₀₄₈.

No Solution Yet Submitted by Danish Ahmed Khan

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Puzzle Answer

Comment 4 of 4 |

The required sum is 1,398,102

Edited on March 21, 2024, 2:27 pm

Posted by K Sengupta on 2024-03-21 14:26:18

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