To solve the equation <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>�</mi><mo stretchy="false">!</mo><mo>+</mo><mn>2</mn><mi>�</mi><mo>=</mo><mo stretchy="false">(</mo><mi>�</mi><mo>+</mo><mn>1</mn><mo stretchy="false">)</mo><mo stretchy="false">!</mo></mrow></semantics></math>x!+2y=(x+1)!, we can simplify it by expanding the factorials and then rearranging terms to isolate <math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>�</mi></mrow></semantics></math>y.
First, let's expand the factorials:
<math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mi>�</mi><mo stretchy="false">!</mo><mo>+</mo><mn>2</mn><mi>�</mi><mo>=</mo><mo stretchy="false">(</mo><mi>�</mi><mo>+</mo><mn>1</mn><mo stretchy="false">)</mo><mo stretchy="false">!</mo></mrow></semantics></math>x!+
|
Posted by Jeffrey Warner
on 2024-03-27 12:08:59 |