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Sum of distinct digit number (Posted on 2024-03-28)

Find the sum of all of the three digit positive integers with three distinct digits.

No Solution Yet Submitted by Danish Ahmed Khan

Rating: 3.0000 (1 votes)

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solution

| Comment 3 of 4 |

Each of the digits 1 through 9 appears 9*8 = 72 times in the hundreds position.

Each of the digits 1 through 9 appears 8*8 = 64 times in the tens position.

Each of the digits 1 through 9 appears 8*8 = 64 times in the units position.

The digits 1 through 9 add up to 45.

45 * (72*100 + 64 * 11) = 355,680

Posted by Charlie on 2024-03-28 09:25:17

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