Find the least number A such that for any two squares of combined area 1, a rectangle of area A exists such that the two squares can be packed in the rectangle (without interior
overlap).
You may assume that the sides of the squares are parallel to the sides of the
rectangle.
The width has to be large enough so that a 1x1 square accompanied by a negligible minuscule square can fit. So the width is 1.
It must be long enough so that two squares of side length sqrt(2)/2 can fit, so the length is sqrt(2).
The area of that rectangle is 1 * sqrt(2) = sqrt(2).
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Posted by Charlie
on 2024-04-01 09:58:11 |
proposed solution
