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Complex Roots Unleashed (Posted on 2024-04-23) Difficulty: 3 of 5
A complex number a≠-1 is the root of an equation x3+1=0.

Find 1+2a+3a2+4a3+5a4.

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution Puzzle Answer | Comment 1 of 7
a^3+1 =0
=> (a+1)(a^2-a+1)=0
=> a^2-a+1=0, since a≠-1.
Now, 5*a^4+4*a^3+3*a^2+2a+1 = (5a^2+9a+7)(a^2-a+1)-6
Since, a^2-a+1 =0, it follows that the value of the given expression is -6.


  Posted by K Sengupta on 2024-04-23 08:39:28
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